(A) Net ionic equation :
CaCO3(s) + 2 HCl(aq) CaCl2(aq) + H2O(g) + CO2(g)
(B)
Number of moles of CO2 = PV/RT = (749/760) atm× 0.656L/(0.0821atm-L/K.mol × 293.15K) = 0.026862mol
Number of moles of CaCO3 = number of moles of CO2
Mass of CaCO3 = 0.026862mol×100g/mol = 2.6862g
= 2.69g. (Answer)
Mass of SiO2 = 3.00 - 2.6862 = 0.3138g = 0.314g (Answer)
Percent CaCO3 = 2.6862/3.00 × 100% = 89.54%
= 89.5 %. (Answer)
(D)
The number of moles of CO2 calculated would be more and hence more number of moles calculated for CaCO3. The results would be higher than the correct percent CaCO3.
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