What must the charge (sign and magnitude) of a particle of mass 1.48 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 680 N/C ? What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?
A)
Force, F = ma = qE
0.00148 x 9.8 = q x 680
Charge, q = - 2.13 x 10^-5 C
B)
Force, F = ma = qE
(1.67 x 10^-27) x 9.8 = (1.6 x 10^-19) x E
Electric field, E = 1.02 x 10^-7 N/C
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What must the charge (sign and magnitude) of a particle of mass 1.48 g be for...
What must the charge (sign and magnitude) of a particle of mass 1.48 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 680 N/C ? Answer is in C
What must the charge (sign and magnitude) of a particle of mass 1.46 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 630 N/C? Use 9.81 m/s^2 for the magnitude of the acceleration due to gravity. What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67×10-27 kg for the mass of a proton, 1.60×10-19 C for the magnitude...
a.) What must the charge (sign and magnitude) of a 1.45 g particle be for it to remain balanced against gravity when placed in a downward-directed electric field of magnitude 650 N/C? Draw a diagram showing the particle, electric field, and forces. b.) What is the magnitude of the electric field in which the electric force it exerts on a proton is equal in magnitude to the proton’s weight? Mass of proton = 1.67262*10^-27 kg Charge of proton = +1.60*10^-19...
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