Question 5 1 pts The time customers spend on the phone for service follows the normal...
A company claims that the time their customers spend waiting in line for service is normally distributed with a mean of 21.4 minutes and a standard deviation of 7.2 minutes. Approximately 10% of the customers can expect to wait as long as how many minutes for service? (with steps please)
Question 33 2 pts 11. The time required for an automotive center to complete an oil change service on an automobile approximately follows a normal distribution, with a mean of 19 minutes and a standard deviation of 2.3 minutes. If the automotive center does not want to give the discount to more than 5% of its customers, how long should it make the guaranteed time limit? Round up your answer. O 16 O 19 14 O 18
1.The time required for an automotive center to complete the service oil change service on an automobile approximately follows a normal distribution, with a mean 19 minutes and a standard deviation of 3 minutes. a. The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take ionger, the customer will receive the service for half-price. What percent of customers recelve the service for half-price? b. If the automotive center does not want to give the...
Assume the commute time is a random variable that follows the normal distribution with a mean of 10.3 minutes with a standard deviation of 4.8 minutes. You wish to calculate the probability that the commute time is more than 16.3 minutes. What is the z value you would look up in the standard normal table to answer this question? What is the probability that the commute time is more than 16.3 minutes? What would be the targeted average commute time...
Question 5. A lahmacun company has found that service times for orders follow a normal distribution with a mean of 40 minutes and a standard deviation of 10 minutes. A random sample of five orders was taken. a) The probability is 0.2 that the sample mean of service times is less than how many minutes? (10 pts) b) What is the probability that more than one of these orders take more than 60 minutes? (10 pts)
The time that university students spend on the internet follows a normal distribution. At flinders university, the mean time is 5 hours with a standard deviation of 1.2 hours. What is the probability that the average time 100 random students on campus willl spend more than 5 hours on the internet? a) 0.5 b) 1 c) 0.2 d) 0
The time required for Speedy Lube complete an oil change service on an automobile approximately follows a normal distribution, with mean of 17 minutes and a standard deviation of 2.5 minutes. Speedy Lube guarantees customers that the service will take no longer than 20 minutes. If it does take longer, the customer will receive the service half-price. What percent of customers receive the service for half price? If Speedy Lube does not want to give the discount to more than...
Q: A study of long-distance phone calls made from General Electric revealed the length of the calls, in minutes, follows the normal probability distribution. The mean length of time per call was 5.5 minutes and the standard deviation was 1.3 minutes. Find the interquartile range of this distribution
Question 5 10 pts The length of time it takes to find a parking space at 10 A.M. follows a normal distribution with a mean of five minutes and a standard deviation of two minutes. Find the probability that it takes at least eight minutes to find a parking space. 0.0668 0.9270 0.5001 0.0001 10 pt= Question 6
The time required for Quick Changers to complete an oil change service on an automobile follows a normal distribution, with a mean of 17 minutes and a standard deviation of 2.5 minutes. Quick Changers guarantees customers that the service will take no longer than 20 minutes, else the service is half-price. If Quick Changers does not want to give the discount to more than 3% of its customers, how long should it make the guaranteed time limit? (Round to the...