Question
15, 16
how do i do these?
ВІ 15.03 pts.) If a sample contains 83% of the Renantiomer and and 17% of the Senantiomers what is the enantiomeric excess of
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Answer #1


15)

S is present in smaller amount
%ee = 100 - 2*S
= 100 - 2*17
= 100 - 34
= 66
Answer: 66

16)
Since there are equal amount of R and S.
The net rotation would be 0
Answer: 0

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