Let the mass of solvent be 1 Kg
m(solvent)= 1 Kg
use:
number of mol,
n = Molality * mass of solvent in Kg
= (5.9 mol/Kg)*(1 Kg)
= 5.9 mol
Molar mass of CH3CO2H,
MM = 2*MM(C) + 4*MM(H) + 2*MM(O)
= 2*12.01 + 4*1.008 + 2*16.0
= 60.052 g/mol
use:
mass of CH3CO2H,
m = number of mol * molar mass
= 5.9 mol * 60.05 g/mol
= 354.3 g
Mass of solution = mass of CH3CO2H + mass of solvent
= 354.3 g + 1000 g
= 1354.3 g
Use:
Mass % of CH3CO2H = mass of CH3CO2H * 100 / mass of solution
= 354.3 * 100 / 1354.3
= 26.2 %
Answer: 26.2 %
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