Question

Draw the Lewis structures of the given molecules. Include lone pairs on all atoms where appropriate. 

OF2 CO2


Draw the Lewis structures of the given molecules. Include lone pairs on all atoms where appropriate. OF CO2 Select Draw Rings


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Concepts and reason

Lewis structure shows bonding between atoms present in a molecule, lone pair of electrons can also be placed on the atoms.

Draw the Lewis structures for the molecules by determining the number of valance electrons of the molecules.

Fundamentals

A pair of valance electrons that does not involve in chemical bond is called as lone pair of electrons.

The molecule OF2{\rm{O}}{{\rm{F}}_2} has central atom oxygen and it is surrounded with two fluorine atoms.

Determine the total number of valance electrons as shown below.

1×ValanceelectronsinOxygen=1×6=6e2×Valanceelectronsinfluorine=2×7=14eTotalvalanceelectrons=20e\begin{array}{l}\\1 \times {\rm{ Valance electrons in Oxygen = 1}} \times {\rm{6 = 6 }}{{\rm{e}}^ - }\\\\2 \times {\rm{ Valance electrons in fluorine = 2}} \times 7{\rm{ = 14 }}{{\rm{e}}^ - }\\\\\overline {{\rm{ Total valance electrons = 20 }}{{\rm{e}}^ - }} \\\end{array}

Draw the Lewis structure of the molecule basing on the total valance electrons of the molecule as shown below.

The molecule CO2{\rm{C}}{{\rm{O}}_2} has central atom carbon atom and it is surrounded with two oxygen atoms.

Determine the total number of valance electrons as shown below.

1×Valanceelectronsincarbon=1×4=4e2×Valanceelectronsinoxygen=2×6=12eTotalvalanceelectrons=16e\begin{array}{l}\\1 \times {\rm{ Valance electrons in carbon = 1}} \times 4{\rm{ = 4 }}{{\rm{e}}^ - }\\\\2 \times {\rm{ Valance electrons in oxygen = 2}} \times 6{\rm{ = 12 }}{{\rm{e}}^ - }\\\\\overline {{\rm{ Total valance electrons = 16 }}{{\rm{e}}^ - }} \\\end{array}

Draw the Lewis structure of the molecule basing on the total valance electrons of the molecule as shown below.

Ans:

Lewis is structure of the molecule is as follows:

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