Question

In an azeotropic solution, the liquid and vapor phases have equal mole fractions of solute at equilibrium. Find the numerical value of the Henrt's Law coefficient that is azeotropic at its standard boiling point. Include units.

Answer 1

50% Vapoo 1 phase liquid Temp 2 phase liquid XB → Two phases of liquid Creating a minimum azotropic mature “The azeotropic mixture ºs boiling H temperature lower than the temperature - Two phases of liquid observed. Henoy's law is used for the determination of Concentoation of mole fraction Of Solution Present at Specific poessure XA — KH Mole fraction Henry Constant

Benzene a water Mole percent system. of water = 29.6% Mole of. of Benzene - - 100-29.6 - 70.4 % = Xo Mole Dercent of Solution 100 XB = 70.4/100 =0.704 PA = KH XA 103 = kn (0.104) Kh = 1.42 x 10 Henry Constant value is 1.42x ios Ethanol - Water System, Mole af. Etot - 89.40 Mole of Water : 100--89.4 = 11.60% Mole percent of Solate/100 = xq

Xp = 89.4/100 = 0.694 13= km (0.894) kn = 111x105 Thus, henry Constant value is lol1 x 105.

Azeotropic Solution : → A mixture of Liquids a constant boiling point. that has has Because, an azeotropic miature may be higher or lower than that of any of its Components. A solution which Desults to large deviation of the Concertration from ideal Behaviour of Dauit's law. leads to a Solution mixture known as Ageotdopes & These mixture usually boils at Constant Temperature. Azeotropes are Two types : → The Solution mixture formed from Negative deviation, Result in maximum boiling azeotrope Benzene - Water Ageoldope at 29.6 mole al Wateo at latm.

The Solution mixture formed from Dositive deviation Desults in minimum boiling azeotrope Ethanol - Wateo at 89.4 mole Peocent Etoh at jatm. → Azeotrope mixture can be formed from maximum boiling Azeotrope or Minimum boiling Azeotrope. While the vapor phase having Equivalent Composition to that liquid phase ...