Question

1. Using the given information answer the following questions with corresponding answers.

(a)

Tryptophan is a diprotic acid (K_a1 = 1.48 $LaTeX: \times$ × 10^-3 and K_a2 = 4.07 $LaTeX: \times$ × 10^-10) that can have three different form in solution: H₂T⁺, HT, and T^-. What would be the pH of the solution containing 0.045M HT?

Group of answer choices

6.86

6.12

7.43

12.23

7.06

(b)

Tryptophan is a diprotic acid (K_a1 = 1.48 $LaTeX: \times$ × 10^-3 and K_a2 = 4.07 $LaTeX: \times$ × 10^-10) that can have three different form in solution: H₂T⁺, HT, and T^-. What would be the concentration of H₂T⁺ in the solution of 0.045M HT?

Group of answer choices

4.2 $LaTeX: \times$ × 10^-5 M

0.80 $LaTeX: \times$ × 10^-5 M

5.1 $LaTeX: \times$ × 10^-5 M

2.3 $LaTeX: \times$ × 10^-5 M

3.7 $LaTeX: \times$ × 10^-5 M

(c)

Tryptophan is a diprotic acid (K_a1 = 1.48 $LaTeX: \times$ × 10^-3 and K_a2 = 4.07 $LaTeX: \times$ × 10^-10) that can have three different form in solution: H₂T⁺, HT, and T^-. What would be the concentration of A^- in the solution of 0.045M HT?

Group of answer choices

0.38 $LaTeX: \times$ × 10^-5 M

3.3 $LaTeX: \times$ × 10^-5 M

1.3 $LaTeX: \times$ × 10^-5 M

2.4 $LaTeX: \times$ × 10^-5 M

4.7 $LaTeX: \times$ × 10^-5 M

(d)

Serine is a diprotic acid (K_a1 = 6.17 $LaTeX: \times$ × 10^-3 and K_a2 = 7.08 $LaTeX: \times$ × 10^-10) that can have three different forms in solution: H₂S⁺, HS, and S^- (Note: S is not sulfur in these formulas). What would be the pH of the solution containing 0.035M Na⁺S^-?

Group of answer choices

9.88

10.23

10.85

9.02

3.15

Answer 1

Tryptophan ihon - HI sincee dit act as aeed amphiprotic so - teigika, & {- leg Kaz} = -deg (1.60*10) + {-lea, 9-03 Xpo"} 2083 +9.39 2 pn 2 6.1 b) 40 K HT Tho To HT 0.04 S es 207 Ro - [nt] Ka, xka - chestia Cuez3

1:49 X 10-3 = 0.045 % 10 [1₂7] 0.045 x 106-11 1.48X10-8. [h, T = 1 = prog5 x 7680 - = 0.045 xlvo X10 1.488 0.0304 x 10 [7] = 2.36 810-SM. since and son HT is amphips he spean, for this [170] ~ [TO) = 2.36X105 4 @ for sout I poly protec acid. pH = 1 2 (p kew + pkan tlge) (14 +-ly (901x15") +, 002) - (14 + 9.150-1.455) Iph alat 10.89