Question

2.6 moles of Sulfur are mixed with 45 moles of fluorine gas and 28 moles of SF6 gas find Emax and Emin. Z8 S8 +24 F2 8 SF6

Answer 1

Se + 24 F2 8 SFG initial 2.6 45 moles Ist of all we have to determine the limiting reagent. I mole 2.6 3. i sq reacts with 24 mole F2 So will react with (24 x 206) more f = 62.4 mole F. Hence, The given amount of it requires (62- 4 mole), F2 (45 mole) is lower than sog F2 is the limiting reagent. Nowo extent of reaction will be maximum when all the limiting reagent will be completely reacted. Son 24 mole 45 mole r gives 28 mole SFG. Fz will give ( 28 x 45) mole sto un 24 - 52.5 mole SFG. son final moles of Sf = (28 + 52.5) more 80. 5 mole.

Hence, final moles of SF - initial moles of sto Imax Stoichiometric wefficent of SFO 80.5 - 28 6.5625. amax = 6.5625 Enun will be when there will be no reaction means final moles of Sf = initial moles of SF e final moles of Sto - initial moles of st 20, un & min = 0 and even - 6.5625 max