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5. Suppose that a person commutes to work by bus. The person arrives at the bus stop at the same time every day. The waiting

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5)

here for uniform distribution parameter a(5 minute) =300 sec and b(10 minutes)=600 (seconds)

a)P(between 5 min and 15 seconds (315 seconds) and 7 minutes and 30 seconds (450 seconds):

probability = P(315<X<450)= (450-315)/(600-300)= 0.4500

b)

P(wait more than 7 minute 45 seconds (465 seconds)

probability = P(X>465)= 1-P(X<465)= 1-(465-300)/(600-300)= 0.4500
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