Question

378 2179,99 Find mo Biz 52179, 904 Bra 3 mer. Br2 1 mol NHW er % yield= 359 100 W 308,09 Find the maximum mass of ammonium bromide that can be made from 45 g of liquid bromine reacting with 13 g of ammonia. j-5 45 - Practice "j", Page 2 of 3

please explain for me what each step do , thank you

Answer 1

Given Reaction 3 G 8 N GNH,,Br N molar mass fN = 17.03) 8/ml motor mass o NHy8T= g7. Iy glmol According to staichiomety f the Raation & dmaf NH amd 3 mol Br mol NHyBr mass = 6x 97»9Yj = 587.447 8x031=136- 2483 3X159.8083 479- 4243 8 met N ma = Hunue for producing 6 mol or 587.6 NBY 136.248 N aund 479-y2y Br 479.424 we nead 136 248 NK needed B 36. 248 3g NaiY need e = 479-424 x 13 d 36 2y8 ys-74 A Bromine ut we hare Hence Bromine Zs limitig reoctant 479-424Bilpredee Nye7-e4 Brwil prodwce NHGBr= S87-9 g ч79. 424 Scanned wh CS CamScanner

45Buailproduce NryBr E87-49uj- 479.424 Maximun massof NH,Br canbe made5S.1S 8 moles 3 mols er, reacts uidth mols of N imal Br reacts uith moles of N= 8males Smals a uail reoct uoith moles rf N= &xsmelu 40moles 13.34 moles Scanned with CS CamScanner