Question

Use the following values if needed needed1.6 4 TIE 1. An electric charge is placed near an object whose net charge is zero. Points5) If the object is made of metal, does the charge exert a force on the object? If so, is it attractive or repulsive? If the object is made of plastic, does the charge exert a force on the object? If so, is it attractive or repulsive? а. Attractive b. Attractive 2. Two charges (a-+2.4ucand Q,-+3.5uGare placed at points A(-3,0,Wm ㎝ ·These charges generate electric field E1 E2 atpoints 0(0,0,0)cm and respectively Points 10) a. Draw arrows indicating the direction of electric ields and E, in figure. b. Find the direction and magnitude of the net electric field at point O Find the direction and magnitude of the net force exerted on an electron if it is placed at point O

answer all parts of both questions, please

Answer 1

1.

a)

Due to the presence of electric charge , the object gets induced charge on it . the surface of object near the electric charge gets opposite charge as that on the electric charge and the farther surface of object gets same charge as the electric charge. hence the object gets attracted towards the charge since the attractive force is greater as compared to the repulsive force.

b)

Due to the presence of electric charge , the object gets induced charge on it . the surface of object near the electric charge gets opposite charge as that on the electric charge and the farther surface of object gets same charge as the electric charge. hence the object gets attracted towards the charge since the attractive force is greater as compared to the repulsive force.

2.

a)

E1 Q1-2.4 x 10-6 C Q2 3.5 x 10-6 C C) E2 r1 0.03 m r2 0.05 m

b)

E₁ = magnitude of electric field by charge Q₁ = k Q₁/r₁² = (9 x 10⁹) (2.4 x 10^-6)/(0.03)² = 2.4 x 10⁷ N/C towards right

E₂ = magnitude of electric field by charge Q₂ = k Q₂/r₂² = (9 x 10⁹) (3.5 x 10^-6)/(0.05)² = 1.26 x 10⁷ N/C   towards left

taking electric field in left as negative and in right as positive

Net electric field is given as

E = E₁ - E₂

E = (2.4 x 10⁷) - (1.26 x 10⁷)

E = 1.14 x 10⁷ N/C

towards right or positive x-direction

c)

q = magnitude of charge on electron = 1.6 x 10^-19 C

magnitude of electric force on the electron is given as

F = q E

F = (1.6 x 10^-19) (1.14 x 10⁷)

F = 1.824 x 10^-12 N

direction : Towards left or negative x-direction ( Since a negative charge experience electric force in opposite direction of the electric field)