Question 1.
[Ag+] = 250 mL * 0.0062 M/(250+250) mL = 0.0031 M
[CO32-] = 250 mL * 0.00014 M/(250+250) mL = 0.00007 M
The ionic product (Kip) of Ag2CO3 = [Ag+]2*[CO32-] = (0.0031)2*(0.00007) = 6.727*10-10
Here, Kip (6.727*10-10) > Ksp (8.1*10-12)
Hence, the formation of precipitate (Ag2CO3) takes place.
1. Precipitation of Ionic Solids 1. 250.0 mL of 0.0062 M AgNO3 and 250.0 mL of...
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