Question

b. Determine what mass of rust can be removed by 540 g of oxalic acid? . Cyanogen, C2N2 is a colorless, poisonous gas that can be prepared by the following: +2 CuCN (a) CN2(+2 K,SO4 (ag) 2 CuSO4 () +4 KCN (a) o a. Determine how many moles of KCN are required to react with 3.7 moles of CuSO4 b. Determine how many moles of cyanogen are produced from 1.75 moles of CuSO4 c. Determine how many moles of K2SO4 are produced from 5.25 moles of CuSO4 d. Determine how many grams of KCN are required to react with 2.5 moles of CuSO4 e. Determine how many grams of cyanogen are produced from 3.5 moles of CuSO4 f. Determine how many grams of cyanogen are produced from 45.3 g of KCN

Answer 1

The given equation s - 3 - 2 Cu Sou caq) + 4 KCN cag) - Cug Wq (q) & 2 kq Soy Cags + 2 Cu Cal can) a gireen : 3.7 medles of cuson to find i moles of ken. solution or from the reaction we can observe that a moles of cuson reacts with a moles of Kow. o I mole of caso reacts with 4= 2 m then, ә) 3.1 MB 0 44 us и Aveo if yol, . : 4 x 2.1 Lºa ka 7.4 moles KEN 2 8 7.4 moles of KCN are required to react % 2.1 Шлок (uke b) 97 м - - 45 лед в С04 I to find i moles of leg Ny. дер? Ром цеh pм и Сам цены - I mole Of Cu, N produced from 2nides usos оя, а lеs B (44 2 kоduсk | cole Cu, N, 1 us GSo4 ресми | щеte Lu, J,

2 -25 КАССА Я СОд үPLAcute Jх | 15 лвСе см,, б. 815 usla Cu, No 1 c) 40мБ• ақ са 9 Cus,00 to find ! moles of Krsoa [46м 84 вме of a Luk, атр Сол | S. 25 yolu 04 сом bеlue Ко, — Autolvo. WEAeg 4, 94 kod и (и | wоlе t 4 (на акосмее 1x5:25 И.ola Sa | 25. 25 и 404 d) given & 2.5 mole I to find grams Cusoy of Ken reaction и Cu04 we can observe & Яu go tk u o 4 ole KA. I from the | a gle I now, R usle о Luko4 : 2 ( 63.5 + 3 2 + 16 x4) Cis04 ? А ( 54, 5) = 39 am 319 я ихся ТА мое k КСА = A ( 29 + 12 + 14 ) 4 - 4 (65) 4k LN - дьо аku . о г » 2-5 ове ле Сл. Слм) 4 г (S. а 2 a's x с. 5 а се, с 218.15 - 150 л

219 314 а в ц04 1 3sdщСА 250в кіл then, 34 15 1 404 ці ( он вдле 260 x 343 кил 22s 2 LAI | e) 4,9 см - 3 S илule4 9 404 ft [nd - 249 9 чашом. (щ, N,) м pH ц Lol uuloh 4 , op mole Cuson = 159.5 g lason 3 3.5 mola Lu04 - 3.5 x ts: 504 С04 а 55 k• 25 2 40, е well T 2. Cu, N, До (62.5x 2 + 14 x 2 1554 , , 1 1. from reaction, we can observe that :- 2 moles of lusos produces Imole My Ng ә 21 4 4 80, p zodще (5 5 4 (ч. 2 2) 550 - 24a (04 pоducед 5 x 558 - 244 4, л, 24 _ 2 2+ + 25 4 Cu, N,

4) \10м. - 45. 2 а вил to find a grams of My We produced. from realtion! - 4 ло(4 9 Lut I adm04 1 шое ш., N, 4 и ред исля 4 ( 34 + 12 + 14) a tw а ми с аво е Кил & I mole Cug N 2 155 g M, Nz ат . 2 Goa KiN p PCabluu 1s 2 Cu, N, :) 45.24 Lt рuo (и са 155 x A5» 2 a la, N, 2bo 2 21 л и , л. YN Ladislaut 3. at a g, n, psduud (9М) 453 4 Co.