A uniform E-field (in N/C) is given by -6i + 2j + 3k. A rectangular box is at rest on the origin of the axis system such that one of its faces has an area of 2.0 m^2 in the y/z plane. What is the magnitude of the electric flux ( in Nm^2/C) through the face? Refer to the situation above, what is the total flux ( in NM^2/C) for the entire rectangular surface of the box?
A uniform E-field (in N/C) is given by -6i + 2j + 3k. A rectangular box...
A uniform electric field of magnitude E = 445 N/C makes an angle of theta = 67.0^degree with a plane surface of area A = 3.80 m^2 as in the figure below. Find the electric flux through this surface. N m^2/C
A uniform electric field of magnitude E = 465 N/C makes an angle of θ = 61.5° with a plane surface of area A = 3.55 m2 as in the figure below. Find the electric flux through this surface.
V76 3k and S be the rectangular region with the orientation shown below. Let +6 (0,0,4) (2,0,4) (0,2,0) (2, 2,0) Find a normal vector to the plane (in the upward direction). -8j 4k n V 80 Find the area vector. (0, — 8, — 4) | х A (2 5 -(2 5 2 2 Flux = 5 6j and S be a disk of radius 4 on the plane z = 10 - x - y oriented away from the...
A uniform electric field of magnitude 3.50x104 N/C makes an angle of 47 ° with a plane surface of area 1.63x10-2 m2 What is the electric flux through this surface? N m2/C Submit Request Ans
6. The electric field in the region of space shown is given by E (8i+2yj) N/C where y is in m. What is the magnitude of the electric flux through the top face of the cube shown? 2n 7. a a Charge of uniform linear density (4.0 nC/m) is distributed along the entire x axis. Determine the magnitude of the electric field on the y axis at y-2.5 m.
Consider a closed triangular box resting within a horizontal electric field of magnitude E = 7.06 x 104 N/C as shown in the figure below. 30.0 cm 60.0 10.0 cm (a) Calculate the electric flux through the vertical rectangular surface of the box. O kNm2/C O (b) Calculate the electric flux through the slanted surface of the box. kNm2/C (c) Calculate the electric flux through the entire surface of the box. kNm2/C Need Help? Read It Watch It
A uniform electric field of magnitude 2.30×104 N/C makes an angle of 37 ∘ with a plane surface of area 1.60×10−2 m2 . What is the electric flux through this surface? I tried using this equation but it was wrong: (2.30x10^4)(1.60x10^-2)sin(37)= -236.82 Thank you for the help in advance
A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface (a) What type of charge distribution is inside the surface? C a positive line charge situated on and parallel to the axis of the cylinder O a negatively charged plane parallel to the end faces of the cylinder C a positively charged plane parallel to the end faces of the cylinder a collection of negative point charges arranged in a line at the center...
The figure below shows a uniform electric field of magnitude E = 440 N/C making an angle of ϕ = 61.0° with a flat surface of area A = 3.60 sq.m. What is the magnitude of the electric flux through this surface (in N · m sq./C)?
In each figure below is shown a rectangular box with dimensions L × W × H, placed in various electric fields of uniform magnitude E. For each case, find an expression for the net electric flux ΦE out of the box in terms of E, L, W, and H. The field in each case is assumed to be perpendicular to the side faces of the box.