Question

1-5 helppp thnx

of Sth a prs Suc Cor Contaaner cs a 4ooomL S atm hind the tt perature NCon rs emperatre d 2c and 1400 mL uar Hh n Con taner 400 tor Fon d of Hh:s the mass gas B Complete the tabe T Pt Vt Ts 2L 250 mL atm 6.5 4tm 1-5m SL 4oo 5L 1-600 000 p-4Ltoo'nl 127C torr 0.4 atm toeo mL 15 or Compete the tabie 4.7 loit d

Answer 1

using itel ger PV = MRT To PV = 1.5x 0.40*44 = [32.2]k MR 0.0821x 10 PV=NRT = = F 0 .0734 mor 900x14 0.082 4X 760x275 mass = mole x molar mass - 0.0734 x 20 = 11:47%

7 poll (un loki 4.7 9.3 50x1010 2x10S 2.94 X10 5.1 12 6.34104 8.9 7.94 X166 to? 10.8 3.2 1126x159 10? 10.8 lo 6.3 Xlo 3. 10.8 - 1018 2 10 + M2 (Pou 6 AgCl lar. 2 Ag, poucart 3 ZnCl₂ cas. Net-lonic esh t e Agt cor.) + el caq.) Ageless