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(37) Problem 5: An electrical power station reques 1.5x 1014 of heat transfer into the one and has an efficiency of 38% at St
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Answer #1

part a)

heat transfers to enviroment = (1 - efficiency) * heat input

heat transfers to enviroment = (1 - 0.38) * 1.5 *10^14

heat transfers to enviroment = 9.3 *1013 J

part b)

ratio of heat transfer to work output = 9.3 *10^13/(0.38 * 1.5 *10^14)

ratio of heat transfer to work output = 1.63

the ratio of heat transfer to work output is 1.63

part c)

work done = 0.38 * heat input

work done = 0.38 * 1.5 *10^14

work done = 5.7 *1013 J

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