A buffer solution is prepared by mixing 78.0 mL of 0.279 M fluorobenzoic acid (C7H5O2F) with...
A buffer solution is prepared by mixing 78.0 mL of 0.279
M fluorobenzoic acid
(C7H5O2F) with 50.0 mL of 0.476
M sodium fluorobenzoate. The pKa of this weak acid is
2.90. What is the pH of the buffer solution? (with correct sig
figs)
Homework Answers
Answer
pH = 2.94
Explanation
After mixing the solution
Concentration of C7H5O2F = 0.279M/( 128ml/78ml) = 0.1700M
Concentration of C7H4O2F- = 0.476M/( 128ml/ 50ml) = 0.1859M
Applying Henderson - Hasselbalch equation
pH = pKa + log([A-]/[HA])
pH = pKa + log( [ C7H4O2F-]/[C7H5O2F])
pH = 2.90 + log( 0.1859M/0.1700M)
pH = 2.90 + 0.039
pH = 2.94
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