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Speedy Delivery Service | Answer 1 | ||||||||
Purchase cost of Truck | 90,000.00 | ||||||||
Painting cost | 4,000.00 | ||||||||
Tyre cost | 600.00 | ||||||||
Engine Overhauling | 4,400.00 | ||||||||
Total cost of Truck | 99,000.00 | A | |||||||
Residual Value | 9,000.00 | B | Date | Asset Cost | Depreciable Cost | Useful Life | Depreciation Expense | Accumulated depreciation | Book Value |
Depreciable Cost | 90,000.00 | C=A-B | 1/3/2018 | 99,000.00 | 99,000.00 | ||||
12/3/2018 | 90,000.00 | 5.00 | 18,000.00 | 18,000.00 | 81,000.00 | ||||
Straight Line Method | 12/3/2019 | 90,000.00 | 5.00 | 18,000.00 | 36,000.00 | 63,000.00 | |||
Depreciable Value | 90,000.00 | See C | 12/3/2020 | 90,000.00 | 5.00 | 18,000.00 | 54,000.00 | 45,000.00 | |
Life | 5.00 | D | 12/3/2021 | 90,000.00 | 5.00 | 18,000.00 | 72,000.00 | 27,000.00 | |
Annual depreciation | 18,000.00 | E=C/D | 12/3/2022 | 90,000.00 | 5.00 | 18,000.00 | 90,000.00 | 9,000.00 | |
Units of Production Method | |||||||||
Depreciable Value | 90,000.00 | See C | |||||||
Life (Miles) | 100,000.00 | F | |||||||
Depreciation per Mile | 0.90 | G=C/F | |||||||
H | I=H*G | Date | Asset Cost | Depreciation Expense | Accumulated depreciation | Book Value | |||
Miles | Depreciation | 1/3/2018 | 99,000.00 | 99,000.00 | |||||
Year 1 | 21,000.00 | 18,900.00 | 12/3/2018 | 18,900.00 | 18,900.00 | 80,100.00 | |||
Year 2 | 21,000.00 | 18,900.00 | 12/3/2019 | 18,900.00 | 37,800.00 | 61,200.00 | |||
Year 3 | 21,000.00 | 18,900.00 | 12/3/2020 | 18,900.00 | 56,700.00 | 42,300.00 | |||
Year 4 | 21,000.00 | 18,900.00 | 12/3/2021 | 18,900.00 | 75,600.00 | 23,400.00 | |||
Year 5 | 16,000.00 | 14,400.00 | 12/3/2022 | 14,400.00 | 90,000.00 | 9,000.00 | |||
Answer 2 | |||||||||
For highest ne income in first year depreciation expense should be lowest. | |||||||||
Among Straight Line Method and Units of Production Method, Straight Line Method has less depreciation of $ 18,000 then Units of Production Method of $ 18,900 by $ 900. So Straight Line Method should be used. |
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