Consider reaction, N 2 (g) + 3 H 2 (g) 2 NH 3 (g)
The standard entropy change of reaction is given as, r S 0 = S 0 ( products ) - S 0 ( reactants )
S 0 ( products ) = 2 S 0 NH 3 (g) = 2 ( 192.45) J K -1 mol -1 = 384.9 J K -1 mol -1
S 0 ( reactants ) = S 0 N 2 (g) + 3 ( S 0 H 2 (g) )
S 0 ( reactants ) = [191.61 + 3 ( 130.68 ) ] J K -1 mol -1 = 583.65 J K -1 mol -1
From above calculated values , we get r S 0 = 384.9 J K -1 mol -1 - 583.65 J K -1 mol -1 = - 198.75 J K -1 mol -1
ANSWER : N 2 (g) + 3 H 2 (g) 2 NH 3 (g) r S 0 = - 198.75 J K -1 mol -1
b)
Consider reaction, N 2 (g) + 5/2 O 2 (g) N2O5 (g)
S 0 ( products ) = 355.7 J K -1 mol -1
S 0 ( reactants ) = S 0 N 2 (g) + 5/2 S 0 O 2 (g)
S 0 ( reactants ) = [ 191.61 + ( 5/2 ( 205.14 ) ] J K -1 mol -1 = 704.46 J K -1 mol -1
From above calculated values , we get r S 0 = 355.7 J K -1 mol -1 -704.46 J K -1 mol -1 = - 348.76 J K -1 mol -1
ANSWER : N 2 (g) + 5/2 O 2 (g) N2O5 (g) r S 0 = - 348.76 J K -1 mol -1
1. Using the relevant Sºvalues listed in Appendix G, calculate AS 298 for the following changes:...
1. Using the relevant Sºvalues listed in Appendix G, calculate AS 298 for the following changes: (a) N2(g)+3H2(g)2NH3(g) (b) N2(g)+5/202(g) ---N2Os(9)
Using the relevant S°values listed in Appendix G, calculate ΔS°298 for the following changes: (a) N2(g)+3H2(g)⟶2NH3(g) (b) N2(g)+5/2O2(g)⟶N2O5(g)
1. Using the relevant S'values listed in Appendix G, calculate AS 298 for the following changes (a) N2(g)+3H2(g) +2NH3(g) (b) N2(g)+5/202(g)—N2O(g) 2. Use the standard free energy data in Appendix G to determine (1) AHan. (2) AS (3) AS., and Aune for cach of the following reactions, which are run under standard state conditions and 25 "C. Identify each as either spontaneous or nonspontaneous at these conditions. (a) C(s, graphite)+O2(g) CO2(g) (6) O2(g)+Nz/g/22NO(g) (c) Cu(s)+S(g)-Cu25(s) (d) CaO(s)+H20(1) Ca(OH)2(s) (e) Fe2O3(s)+3CO(g)...
9. Calculate ASⓇ, ASsurr, AStot, and AGⓇ at 298 K for the following reaction N2(g) + 3H2(g) → 2NH3(g) at 25*C. AH° = -92.22 kJ/mol Using: Smº[N2, gas) = 191.6J/(K-mol); Sm"[H2, gas) = 130.7J/(K-mol); Sm*[NH3, gas) = 192.4
Using values from Appendix C of your textbook, calculate the value of Kea at 298 K for each of the following reactions: (a) 2 SO3(g) 2 SO2(g) O2(g) Кeg (b) 2 NO(g) N2(g)02(g) Кeg (c) 2 NH3(g) N2(g) +3 H2(g) Кeg
1. Consider the reaction: 2NH3(g) → N2(g) + 3 H2 (8) AG = +33.3 kJ a. Is this reaction spontaneous? Explain. b. Predict the sign of AS. Explain. C. Based on your answer to part b, is this reaction exothermic or endothermic? Explain. For the reaction N2(g) + 3H2(g) 2NH3 (8) a. Using values in Appendix Cin your book, calculate AHⓇ and AS. b. Assuming that AHºand ASº don't change with temperature, calculate the value for AG at 400K Is...
+92 5) 2NH3(g) → 3H2(g) + N2(g) AH 298 = 92kJ/molrxn According to the information above, what is the standard enthalpy of formation, AHOF, for NH3 (g) at 298 K ?
Using values from Appendix C of your textbook, calculate the value of Keq at 298 K for each of the following reactions: Using values from Appendix C of your textbook, calculate the value of Keg at 298 K for each of the following reactions: (a) Fe3O4(s) + 4 CO(g) = 3 Fe(s) + 4 CO2(g) Keq = (b) Fe2O3(s) + 6 HCI(g) = 2 FeCl3(s) + 3 H2O(g) Keq = D . (c) 4 NH3(g) + O2(g) = 2 N2H4(9)...
1 2 Part A Calculate Kp at 298 K for the reaction NO(g) + + O2(g) → NO2 (g) assuming that AH is constant over the interval 298-600 K. Kp = 2.31x106 Submit Previous Answers ✓ Correct Part B Calculate Kp at 477 K for this reaction assuming that AHR is constant over the interval 298-600 K. PO AQ * o o ? Kp = | Submit Previous Answers Request Answer Revie For the reaction 2CH4 (g) = C2H2(g) +...
Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g)+ 3N20(g)- 4N2(g)+ 3H20(g) ANSWER kJ Using standard heats of formation, calculate the standard enthalpy change for the following reaction. N2(g)+3H2(g)2NH3(g) kJ ANSWER