Question

6.1.5 Question Help A research company polled a random sample of 528 teens about Internet use. 48 % of those teens reported going online several times a day-a fact of great interest to advertisers. Complete parts a through c below. a) Explain the meaning of p 0.48 in the context of this situation. O A. The meaning of p 0.48 is that the researchers have 95 % confidence that 48 % of the 528 teens in the sample said they go online several times a day. OB. The meaning of p 0.48 is that the researchers have 95 % confidence that 48 % of all U.S. teens would say that they go online several times a day O C.The meaning of p 0.48 is that 48% of the 528 teens in the sample said they go online several times a day. This is the researchers' best estimate of p, the proportion of the 528 teens in the sample who said they do so. D. The meaning of p 0.48 is that 48 % of the 528 teens in the sample said they go online several times a day. This is the researchers' best estimate of p, the proportion of all U.S. teens who would say they do so. b) Calculate the standard error of p SE(6)- (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer. 1 part remaining Clear All Check Answer

Answer 1

SE($\widehat{p}$)

$= \sqrt{\frac{0.48*(1-0.48)}{528}}$

= 0.022