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el C : 1.106 C 1. Two identical small balls are held 0.20 m apart. Each has an excess negative charge that results in an electric force of 4.57*10 on each? N in magnitude. Based on this, how many excess electrons are Help with electric force problem will give a like ! Thanks
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Answer #1

For identicle ball the charges on ball are equal-

Let magnitude of charges are q1 and q2.

q1=q2=q

Distance between charges (r) =0.2m

The electric force -

F =kq1q2/r​​​​​​2

where k=8.99x109N-m2/c​​​​​​2

F=4.57x10-21N= 8.99x109xq2/0.22​​​​​​

q=1.43x10-16c

q1=q2=1.43x10-16c Ans

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