A stunt man drives a car at a speed of 20 m/s off a 26-m-high cliff. The road leading to the cliff is inclined upward at an angle of 20∘
Part A:
How far from the base of the cliff does the car land?
Express your answer to two significant figures and include the appropriate units.
Part B:
What is the car's impact speed?
Express your answer to two significant figures and include the appropriate units.
Initial Velocity =20m/s at 20 degrees
so
The car will rise a little then falls
Consider the vertical motion of car
Rise
Use Formula
(at max height velocity becomes zero)
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Time taken to rise
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Falling
Falling Height =y +cliff height =2.385m +26m =28.385m
Time for falling
Use formula
Initial velocity is Zero
-----------
Total time,
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Consider the horizontal motion of car
There is no acceleration in horizontal direction
Speed =Distance /time
Distance=Speed*time
Part A: ANSWER:
=======================
Part B
remains same
so
Vertical motion
Use Formula
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ANSWER:
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