Question

9. At what distance would the repulsive force between two electrons have a magnitude of 4.0 N? (1 point) O8.0 x 10-20 m O7.6 x 10-15 m 5.8 x 10-29 m 01.9x10.5 m 10. Two like charges of the same magnitude are 1.0 mm apart. If the force of repulsion they exert (1point) upon each other is 5.0 N, what is the magnitude of each charge? The constant of proportionality for the Coulombic force is 9.0 x 10°N-m-/c2 045 x 104 C O2.4x 10-5 c O2.4 x 102 c 02.4 x 10-8 c

Answer 1

Charge on electric q = -1.6 times 10^-99C force between two electrons = 4n F = Kq_1 q_2/r^2 rightdoublearrow 4 = 9 times 10^9 times (1.6 times 10^--19)^2/r^2 r^2 = 9 times 10^9 times 2.56 times 10^-38/4 = 5.76 times 10^-29 r = 7.61 times 10^-15 m option(b) \r\n 10. R = 1mm = 1 times 10^-3m F = 5N K = 9 times 10^9 Nm^2/c^2 Now, F = Kqq/r^2 rightdoublearrow 5 = 9 times 10^9 times q^2/(10^-3)^2 q^2 = 5 times 10^-6/9 times 10^9 = 0.5555 times 10-15 c^2 q = 0.236 times 10^-7 C q = 2.4 times 10^-8 C option d