20 and 21 Question 20 1 pts An object moves in along the x-axis with an...
An object moves in along the x-axis with an acceleration given by: a = 4t (m/s2). The position of the object at t=0.0 is 7 m, and its velocity at t=0.0 s is 5 m/s. Calculate the position at t=6 s.
A small object moves along the x-axis with acceleration Constants Part A A small object moves along the z-axis with acceleration ar(t)-(0.0320 m/s) (15.0 s t). Att 0 the object is at14.0 m and has velocity v0 6.70 m/s. What is the r-coordinate of the object when t 10.0 s? Express your answer with the appropriate units IA 13.33 Im Submit Pra Previous Answers Request Answer X Incorrect; Try Again; 6 attempts remaining Provide Feedback
An object is at x at t and moves along the x axis according to the velocity-time graph shown below v (m/s) 20 10 -10 (a) What is the object's acceleration between 0 and 4.0 s? m/s2 (b) What is the object's acceleration between 4.0 s and 9.0 s? m/s2 (C) What is the object's acceleration between 13.0 s and 18.0 s? m/s2 (d) At what time(s) is the object moving with the lowest speed? (If there is more than...
An object moves along the x-axis with its position x, in meters, given as a function of time t, in seconds, by x(-1.417-9.491+ 4.68 r(t)-1.41 t2-9.4% + 4.68 What is the object's velocity at time t 1.01 s? Number m/ s
A velocity-time graph for an object moving along the x axis is shown in the figure. Every division along the vertical axis corresponds to 1.50 m/s and each division along the horizontal axis corresponds to 1.50 s. v (m/s) fs (a) Plot a graph of the acceleration versus time. Choose File no file selected This answer has not been graded yet. (b) Determine the average acceleration of the object in the time interval t = 7.50 s to t =...
a small object moves along the x-axis with acceleration ax(t) =-(0.0320m/s3)(15.0s-t). at t=0 the object is at x=-14.0m and has velocity v0x =4.50 m/s. what is the x-coordinate of the object when t=10.0s?
A small object moves along the x-axis with acceleration ax(t) = −(0.0320m/s3)(15.0s−t). At t = 0 the object is at x = -14.0 m and has velocity v0x = 5.90 m/s. What is the x-coordinate of the object when t = 10.0 s?
The position of a particle as it moves along the x axis is given for t > 0 by x = (t^3-3t^2+6t)m. Where is the particle when it achieves its minimum speed (after t = 0)?
An object moves along the y axis according to the equation y(t) = b + ct3, where b = 7.50 m, c = 3.50 m/s3, and y(t) will be in meters when t is entered in seconds. Determine the following. (a) average velocity of the object during the time interval t = 1.00 s to t = 3.00 s m/s (b) instantaneous velocity at the time t = 2.00 s m/s (c) acceleration of the object at the time t...
A particle moves along the x axis according to the equation x = 1.91 2.99t-1.00e, where x is in meters and t is in seconds. (a) Find the position of the particle at t 2.90 s (b) Find its velocity at t- 2.90 s m/s (c) Find its acceleration at t 2.90s m/s? My Note (a) Can the velocity of an object at an instant of time be greater in magnitude than the average velocity over a time interval containing...