Answer:-
Given:-
wt. of empty graduated cylinder = 3.25 g
wt. of empty graduated cylinder + wt. of sodium thiosulfate = 76.373 g
volume of water added to graduated cylinder (V) = 170.95 mL
As we know that
wt. of sodium thiosulfate (m) = (wt. of empty graduated cylinder + wt. of sodium thiosulfate) - (wt. of empty graduated cylinder)
wt. of sodium thiosulfate (m) = 76.373 g - 3.25 g
wt. of sodium thiosulfate (m) = 73.123 g
So the concentration of a solution of sodium thiosulfate is obtained by 73.123 g of solid sodium thiosulfate dissolved in 170.95 mL of water i.e total volume of solution.
therefore
the concentration of a solution of sodium thiosulfate (c) = wt. of sodium thiosulfate (m) / volume of water added to graduated cylinder (V)
the concentration of a solution of sodium thiosulfate (c) = 73.123 g / 170.95 mL
the concentration of a solution of sodium thiosulfate (c) = 0.43 g / mL (i.e the answer)
or
the concentration of a solution of sodium thiosulfate (c) = 0.43 g.mL-1 (i.e the answer)
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