b)
For Young adult:
n1 = 800, p̂1 = 0.37
For parents:
n2 = 300, p̂2 = 0.27
α = 0.05
Null and Alternative hypothesis:
Ho : p1 = p2
H1 : p1 > p2
Test statistic:
z = (p̂1 - p̂2)/√ [(p̂1*(1-p̂1)/n1)+(p̂2*(1-p̂2)/n2) ]
= (0.37 - 0.27)/√[(0.37*0.63/800) + (0.27*0.73/300)] = 3.25
p-value = 1- NORM.S.DIST(3.2472, 1) = 0.0006
p-value < α, Reject the null hypothesis.
6. 1 points P A PODStats 11.00 A report sumanes a survey of people in two...
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