Im not sure if i did number 8 correctly and i need help with the bonus...
i need help with the bonus question CO 498 Energy (kJ/mol) .C=O bond in CO2 CEO 799* 1072 L2 [C=o] + 0 80] -2 Co=c=0) Bonus question: 2 (1072) + 498-2(Z (799)) -> (554) The active ingredient in the antacid Tums is calcium carbonate, Caco, What volume of 0.15 M stomach acid (HCH could be neutralized by a dose of two tablets, each containing 500.0 mg of the active ingredient? --> 1000 mg MM of CaCO₃=100.0869 g/mol