(a) What is the maximum torque (in N.m) on a 160 turn square loop of wire...

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Question

(a) What is the maximum torque (in N.m) on a 160 turn square loop of wire 18.0 cm on a side that carries a 47.0 A current in

Answer 1

Answer #1

a)

for the torque acting on the loop

torque = N*Area of loop * current * magnetic field* sin(theta)

for the maximum torque

theta = 90 degree

maximum torque = 160 * 0.18^2 * 47 * 1.60

maximum torque = 389.8 N.m

b) when theta = 10.9 degree

torque = 160 * 0.18^2 * 47 * 1.60 * sin(10.9 degree )

torque = 73.7 N.m

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Answer 2

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