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Problem 3.15 In Charleston, a city of temptations, the average weekly family (no kids, less than 5 years married) expenditure on entertainment is $60, with a standard deviation of $14 What is the probability that 75 couples (no kids, less than 5 years married) spend less than $57 per week in entertainment? a. b, what amounts of average weekly spending would the sample have in order to be within 1.3% of the population mean? c. What is the probability that the sample mean entertainment expenditure would be greater than $63.5? please show the excel formulas and calculations. thank you!!

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