reaction is F2 + 2XBr --------> Br2 + 2XF
5.700 g of XBr reacts and 3.827 g of Br2 formed
molecular weight of Br2 = 159.808 g/mol
moles of Br2 formed = 3.827/159.808 = 0.0239 mol
so according to the reaction moles of XBr = 2* 0.0239 = 0.0478 mol
weight of XBr = 5.700 g = 0.0478 mol
molecular weight of XBr = weight of XBr / moles of XBr = 5.700 g / 0.0478 mol = 119.247 g/mol
so molar mass of X = 119.247-79.904 = 39.343 g/mol
so the element is Potassium (K)
Consider this reaction involving an unknown element X. F + 2 XBr Br + 2 XF...
Westion of Consider this reaction involving an unknown element X. F,+ 2 XBr - Br, +2 XF When 5.700 g of XBr reacts, 3.827 g of Br, is produced. Calculate the molar mass of X, and then identify its element symbol. molar mass of X: g/mol g/mol element symbol for X:
Consider this reaction involving an unknown element X. F. + 2 XBr Br, + 2 XF When 7.900 g of XBr reacts, 3.362 g of Br, is produced. Calculate the molar mass of X, and then identify its element symbol. molar mass of X: g/mol element symbol for X:
Consider this reaction involving an unknown element X. F. + 2 XBr —Br, + 2 XF When 2.900 g of XBr reacts, 1.234 g of Br, is produced. Calculate the molar mass of X, and then identify its element symbol. molar mass of X: g/mol elem
Consider this reaction involving an unknown element X. F 2 + 2 XBr ⟶ Br 2 + 2 XF When 7.000 g of XBr reacts, 4.700 g of Br 2 is produced. Calculate the molar mass of X, and then identify its element symbol.
nment Score: 200/300 Resources Give Up? Mint muestion 2 of 3 > Consider this reaction involving an unknown element X. F2 + 2 XBr Br + 2 XF When 8.600 g of XBr reacts, 4.790 g of Br, is produced. Calculate the molar mass of X, and then identify its element symbol. molar mass of X: g/mol element symbol for X: c y policy of us contact us help
please help Assignment Score: Glve Up? Hint 2572/5200 Resources Check Answer < Question 39 of 52> Consider this reaction involving an unknown element X. Br, +2 XF F2+2XBR When 7.500 g of XBr reacts, 4.324 g of Br, is produced. Calculate the molar mass of X, and then identify its element symbol. element symbol for X: g/mol molar mass of X: help terms of use contact us privacy policy about us careers
19-KOBKO Activities and Due Dates Topic 14 Skills Practice Video E Hint Check Resources nment Score: 0/300 Question 2 of 3 Consider this reaction involving an unknown element X F, +2XBrBr, + 2XF When 1.900 g of XBr reacts, 0.7134 g of Br, is produced. Calculate the molar mass of X, and then identify its element symbol. element symbol for X: g/mol molar mass of X: contact us help terms of use privacy policy about u careen MacBook Air 888...
QUESTION 1 A 20.0 mL sample solution contains unknown amount of bromide ion (Br). To this solution was added the solution that contains plenty of AgNO3. AgBr precipitates were formed. The precipitate were filtered and measured to be is 0.6964 g. What is the molarity of bromide ion in the original sample solution? The molar mass of Br = 80.0 g; the molar mass of AgBr = 188 g. (Solution) AgNO, is soluble and thus exists Ag+ ion and NO3-ion....
An unknown element (Element X) has three naturally occurring isotopes. Complete the table by filling in the missing percent abundance (2 decimal places). Then calculate the atomic mass of element X (1 decimal place) and determine its identity by filling in its atomic symbol (case sensitive). Isotope Abundance (%) Atomic Mass (amu) 23.985042 1 78.99 2 24.985837 10.00 3 25.982593 amu Atomic mass of element X (1 decimal place): Atomic symbol of element X:
Question A 20.0 mL sample solution contains unknown amount of bromide ion (Br). To this solution was added the solution that contains plenty of AgNO3. AgBr precipitates were formed. The precipitate were filtered and measured to be is 0.6964 g. What is the molarity of bromide ion in the original sample solution? The molar mass of Br = 80.0 g; the molar mass of AgBr = 188 g. (Solution) AgNO, is soluble and thus exists Ag+ ion and NO3-ion. Ag+...