Question

give the of the common name compound

Answer 1

propyl 2-bromo-3-methylbutanoate Longest carbon chain has 4 carbons, the rootword is "but" Since in the given compound no double or triple bonds are present, the suffix is "ane". Here bromine group is substitutent at 2 nd carbon atom and methyl group is substitutent at 3 rd carbon atom .Ester (-oate ) is a funcational group.

The IUPAC name of the any compound contains 3 parts prefix+ rootword + suffix Prefix = any substitutents rootword = longest chain containing most number of carbons if the chain contains 1 carbon = meth 2 carbon = eth 3 carbon = prop 7 carbon = hept 4 carbon = but 8 carbon = oct 5 carbon = pent 9 carbon = non 6 carbon = hex and so on Suffix = if the compound contains single bond (C-C) only then suffix 'ane' double bonds (C=C) 'ene triple bonds yne For selecting prefix numbering, the substituents numbers has to be given in such way that the sum of the all substituents should be as less as possible. For selecting rootword chain, the chain with more number of carbons has to be selected In all the given compounds alkanes are present, hence the suffix is 'ane' in all the four compound For all the compounds, blue coloured part of the name is prefix red coloured part of the name is rootword and pink coloured part of the name is suffix