2. There are 10 children in a given family. Assuming that a boy is as likely...

Question

Question

Answer 1

Answer #1

Given

n=10

P(boy)=p=0.5

X=number of boys the family having

Here P remains same for each baby.

n is prefixed.

X follows Binomial distribution with (n=10,p=0.5)

Probability that family having

A) 5 boys and 5 girls

=p(x=5)

=¹⁰C₅ *(0.5)^5 *(0.5)^5

=0.2461

B) 3 to 7 boys

=p(3 < x< 7)

=p(x=3)+p(x=4)+...+p(x=7)

=0.1172+0.2051+0.2461+0.2051+0.1172

=0.8906

Answer 2

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