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Vectors A and B lie in an xy plane. A has magnitude 3.2 and angle 139 relative to +x direction; B has components B--6.48 and By -6.50. What are the angles between the negative direction of the y axis and (a) the direction of A (b) the direction of the product A x B,and (c) the direction of A x B 3.00k?Please draw a picture and write out all vectors clearly. Thanks!

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Answer #1

Vector A = -3.2 cos 41 i + 3.2 sin 41 j

= -2.415i + 2.1j

Vector B = -6.48i - 6.5j

a) angle between negative axis of y-axis and direction of A = (90 + 41) = 131 o

b) A X B = [ i j k]

[2.415 2.1 0]

[-6.48 -6.5 0]

= i(0 - 0) - j(0 - 0) + k(-15.7 - (-13.6))

= -2.1k

angle is 90o

c

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