Question

1. In Figure 19.1 the Figure 19.1 the equivalence point is at point D. a. If 40.00 mL of C = 0.106 formic acid HOOCH) is titrated NaOH, what is the volume of titrant, NaOH, required to equivalence point D. ant, NaOH, required to reach the 1) is titrated with 0.212 M b. At point D., the titrated solution is basic. Show the reaction that is responsible for the basic pH at the equivalence point D. 2. Using the Ka for formic acid, calculate the pH at the equivalence point D. for titration described in Question 1.

Answer 1

millimales of HCOOH - 400040.106 me 4.24 at Equivalence poënt :- volume of titrant needed to reach = 5000mL moles of acid moles of base 424 = 0.212 x V V = 20 ML volume of titraut: 20.00 mL b) reaction:- HCoocaq) + H2O → HCOOH caq) + Office CO Kaof formic acid = 1.8x10 t 1 pka = 3.74 pH = 7+ % Cpka tlogo) = 7+ % (3.74 +000-0707) pH 8.29