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Part A How many liters of a 0.10% (m/v) KCHIV solution can be prepared from 3.0 L of a 35% (m/v) stock solution? Express your

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Answer #1

Part A : Volume = 110 L     (exact volume is 105 L)

Explanation

According to dilution law,

C1 * V1 = C2 * V2

where C1 = initial concentration = 3.5 %

V1 = initial volume = 3.0 L

C2 = final concentration = 0.10 %

V2 = final volume

V2 = V1 * (C1 / C2)

V2 = (3.0 L) * (3.5 % / 0.10 %)

V2 = (3.0 L) * (35)

V2 = 105 L

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