Question

Question 14 of 14 What is the wavelength of light emitted when an electron transitions from n 5 to n = 2 in a hydrogen atom? nm

Answer 1

Wavelength will be 433.9 nm.

n*5 unitial Solution Given. is transition of election from n=5 3 to n=2 in hydrogen atom. Hence, Minitial =5, nfinal = 2 ner de final- - Now. for hydrogen -2.18x10-18 3 1 - to 3. AE = Eg- Es = -218x10*-( = -2.18x10-18 j ( 1 -2] DE = 67-6° = –2-18 -18 - 2:18 X10' 25-4 100 = -2,18x10718 (122) AE = -41518 X 10-19 Accobeling to Boho's Correspond Prínciple, the. energy š nould correspond to energy of incoming Photon to do the transition." in IAE| = Ephoton = hv = he h= plank's constant = 6.626 X10-34 yis C = 2.998 X 108 m/s Now i= he 1 = (6-626 X10944.)x(2.998 8168 m\A) 4,578 * 10-19 X

Now Die l= 4.339 8.10-7 m Convert (m) unto com) Tlm = loanm deb 10 hา 1 = 4.339X107 X 109 nm = 4:339.X102 nm - Albo nm = 4339 winami - - Doo 11=433,9 nm