The activity (concentration) of a solid is taken as unity.
So, [NH4HS] = 1
Hence
K = [NH3][H2S]
#11/12 8. [H3O+] = 4.3 x 10-3M Instructions: Calculate the [H3O+] of solutions a and b; calculate the [OH-] solutions c and d. 9. pH = 2.76 - PH=-lag (H3ot) 10-PP- 69 H 10-2.76 10. pH = 3.65 11. POH = 3.65 12. pOH = 6.87 Equilibrium and Le Chateleir's Principal Instructions: Write the equilibrium expression for each chemical equation. 1. 2 H250 = 2H26 +526) = [ta?? (s. 1ST 2. NH,HS(s) = NH3(g) + H2560)
Equilibrium and Le Chateleir's Principal Instructions: Write the equilibrium expression for each chemical equation. 2 H2Sg⇌2H2g+S2g NH4HSs⇌NH3g+H2Sg Oxidation-Reduction Reactions Instructions: Assign an oxidation state to each element, ion, or molecule. Cl- Br2 K Ca2+ Instructions: Assign an oxidation state to each atom in each compound. NaCl CH4 SbCl5 Al2O3 Instructions: Assign an oxidation state to each atom in each polyatomic ion. NH4+ Cl04- Cr2072- Mn04- Instructions: Identify the oxidation state of P in each ion. PO43- HPO42- H2PO4- H3PO4
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