Question

A 32.0 kg child takes a ride on a Ferris wheel that rotates four times each minute and has a diameter of 21.0 m. (a) What is the centripetal acceleration of the child? m/s toward the center of the path (b) What force (magnitude and direction) does the seat exert on the child at the lowest point of the ride? magnitude N direction (from upward) (c) What force does the seat exert on the child at the highest point of the ride? magnitude direction (from upward) (d) What force does the seat exert on the child when the child is halfway between the top and bottom? magnitude C N direction from upward)

Answer 1

1)a= w²r = (4×6.28/60 )²×10.5 =1.8m/ sec²

2)F =m(g+a) = 32(9.8+1.8) =371.2N upwards

3)F = m(g-a) = 32(9.8-1.8) = 256N upward

4) F=mg = 32×9.8=313.6N