The balanced equation is
2 C4H10 + 13 O2 ----> 8 CO2 + 10 H2O
From the balanced equation we can say that
2 mole of butane requires 13 mole of O2 so
0.551 mole of butane will require
= 0.551 mole of butane *(13 mole of O2 / 2 mole of butane)
= 3.58 mole of O2
But we have 0.119 mole of O2 which is in short so O2 is limiting reactant
Therefore, the limiting reactant is O2
From the balanced equation we can say that
13 mole of O2 produces 8 mole of CO2 so
0.119 mole of O2 will produce
= 0.119 mole of O2 *(8 mole of CO2 / 13 mole of O2)
= 0.0732 mole of CO2
Therefore, the number of moles of CO2 produced would be 0.0732 mole
For the following reaction, 0.551 moles of butane (C4H10) are mixed with 0.119 moles of oxygen...
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