Question

Suppose a single electron orbits about a nucleus containing two protons (+2e), as would be the case for a helium atom from which one of the naturally occurring electrons is removed. The radius of the orbit is 4.22 × 10^-11 m. Determine the magnitude of the electron's centripetal acceleration.

Answer 1

Solution,

Force, F = ma = (k x 2e^2)/r^2

Acceleration, a = (k x 2e^2) / m r^2

a = (9 x 10^9 x 2 x (1.6 x 10^-19)^2)/(9.1 x 10^-31 x (4.22 x 10^-11)^2)

Acceleration, a = 2.84 x 10^23 m/s^2

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