Question

When a sealed bulb containing a gas is immersed in an ice bath, it has a gas pressure of 387 Torr. When the same bulb is placed in an oven, the pressure of the gas rises to 765 Torr. What is the temperature of the oven in Celsius?

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Answer 1

Temperature of oven = 267 ^oC

Explanation

According to Gay-Lussac's law, absolute temperature of an ideal gas is directly proportional to its pressure, provided amount of gas and volume remains constant.

Mathematically, T₂ / P₂ = T₁ / P₁

where T₁ = initial temperature of gas = temperature of ice bath = 0.0^oC = 273 K

P₁ = initial pressure of gas = 387 torr

T₂ = final temperature of gas = temperature of oven

P₂ = final pressure of gas = 765 torr

Substituting the values,

T₂ / (765 torr) = (273 K) / (387 torr)

T₂ = (273 K) * (765 torr / 387 torr)

T₂ = (273 K) * (1.9767)

T₂ = 537.65

T₂ = 267 ^oC