net acceleration of the object
a = g ( sin x + u cos x) = 9.8 ( sin 44.5 + 0.43 cos 44.5)
a = 9.8745 m/s^2
velocity just before leaving the roof surface
v^2 = 15^2 - 2* 9.8745* 10
v = 27.51 m/s
max height reached by projectile
H = 10 sin 44.5 + ( v sin 44.5)^2/ ( 2g
H = 25.977 m
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