8.3.33-T Question Help In a recent survey, 154 of 460 employees responded that they typically took...

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math Statistics-And-Probability

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Answer 1

Answer #1

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95% CI = 0.2917 < P < 0.3779

$CI = p \pm z* \sqrt {(p*(1-p)/n)}$

Confidence Interval Estimate for the Proportion

Data
Sample Size	460
Number of Successes	154
Confidence Level	95%

Intermediate Calculations
Sample Proportion	0.3348
Z Value	1.9600
Standard Error of the Proportion	0.0220
Interval Half Width	0.0431

Confidence Interval
Interval Lower Limit	0.2917
Interval Upper Limit	0.3779

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In a survey of 1,100 organizations, 710 responded that "the need for collaboration among an increasing...

In a survey of 1,200 organizations, 690 responded that "the need for collaboration among an increasing...

In a survey of 2004 adults in a recent year, 1381 say they have made a...

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1. In a survey of 2289 adults in a recent year, 1440 say they have made...

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In a survey of 2283 adults in a recent year, 1366 say they have made a...

8.3.33-T Question Help In a recent survey, 154 of 460 employees responded that they typically took...

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