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5. An aerosol spray can with a volume of 250. mL contains 2.30 g of propane...

5. An aerosol spray can with a volume of 250. mL contains 2.30 g of propane gas (C3H8) as a propellant.

a. If the can is at 21 ∘C, what is the pressure in the can?

b. What volume would the propane occupy at STP?

c. The can says that exposure to temperatures above 130 ∘F may cause the can to burst. What is the pressure in the can at this temperature?

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Answer #1

1 mores of propane got = man 2.30 = 0.0523 molas mans 44 a) T= 21°C= 294.15k s.Ou6 atu -0.05234 0.082x294.15 P= HRT = 0.0523

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> What is R in this equation and how do you know that it is .082?

Brianna Martinez Thu, Dec 16, 2021 6:36 PM

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