Question

+ -12 points SerPSE10 24.1.OP001 A small object with a charge of q = 10.0 μС travels from the origin to the point x, y = 20.0 cm, 50.0 cm in the presence of a uniform electric field E = 250 V/m. Determine the following. (a) the change in the electric potential energy (in J) of the object-field system (b) the electric potential difference (in V) through which the object moves Need Help? Readt

Answer 1

Solution

=> using the formual for change in energy,

=>change in potential energy = W = -qEd
Given
           E = 230 i V/m
           q = +15.0µC
           d = 0.20i + 0.50j

   ΔU = - (10μC) * (250 i V/m)*(0.20i )
   = - 5 x 10^-4 J  

b)potential difference is equal to
                 ΔV = ΔU / q
                       = - 5 x 10^-4 J / 10μC
                       = - 50 V

if answer in negative doesn't work try with positive.

thanks