Question

Lab #19; Empirical Formula of Magnesium Hydroxide Pre-Lab Questions Name: Heating 1.29 g of gallium gives a gallium-oxygen compound with a mass of 1.739 Calculate the empirical formula of the compound. Step 1: Figure out how many grams of oxygen are in the 1.73 grams of gallium-oxygen compound. Step 2: Convert the 1.29 g of gallium to moles: Step 3: Convert the grams of oxygen you calculated in step 1 to moles: Step 4: Figure out the formula. Formula Name

Answer 1

Solution ;- Given thaedia mass of Grallium-oxygen Compowned =1739 - mass of Grallium = 1:29g step.ti mass of oxygen= mass of Gallium-oxygen compound -- mass of Gran = (1.73 – 1,29)=) 0:449 step-2 1.29g gellium to moles. molar mass of Grallium = 69.72 g/mol so moles of Greellium = 1.299 69.729Imo) = 0.01850 mole step-3 mass of oxygen = 0.44g (step-1) molar mass of oxygen = 16 g/mol So moles of oxygen = 0.449 +0.0275 mol T6 g/mol = 002 15 mol To get mole Ratio divide each element mole by teast Cofficient (0.01850) For Gallium (Go) = 0.01850 mole => 1 0.01850 mole : Oxygen (0) = 0.0275 mole 1.486 4115 0.01850 mole, To get whole number multiply by Simcell cofficient 2 For Gia 1x2 =2 o 15X2 = 3 . so. Empirical formula (Graz Oz. A :.. .. Name + Grallium oxide