Question

Using orbitals, draw the transition state of the SN2 reaction between sodium cyanide and bromomethane. Which orbitals are interacting with which? Why is the bond breaking? Why is the orientation important? Is there another angle besides backside attack that could theoretically work based on orbital geometry? Why doesn’t this happen?

Answer 1

Nee OBV Odbital picture die an of the transition slate Neo Ne Or ow the lobende ord on the CNS. orbital will attack of the one of the lake of entitalot ackyle Cwhich has made to charadeith the u fransition slate) Brwill leave the opposite lobe of that & orbital whithe Pattache hanbeen taken plance The bond it not breaks then the carbon will be of pentavalen and it not possible since carbon has a novalent orbitals to to accomodate para ele nos The Backside attack is very important, as it is less congested and thus the readion sets easily. If the front side atlock ont orientation & There it will be highly engesteld, as follows, t EN • No other backsicle angle in theoritically possible, since it has the minimum amount of energy and it's lost amount W e of Bleric congestion.