Question

1. Three charges are arranged in a triangle with side length L-2cm All three charges equal 2nC. Find the net force (components, magnitude, and direction) on charge C 2. Three charges are arrangedin a riht trianole with

Answer 1

Since all the charge are of like polarity, the force are attractive in nature. Let force due charge A and B be F_A and F_B respectively Resolving F_A & F_B along the two coordinate axis is we get F_H_A and F_H_B along -i^^and i^^and F_x = F_V_A + F_V_B along -j^^(F_V_A and F_V_B are vertical components of F_A and F_B respectively) Now, F_A = 1/4pi epsilon_0 times g_A g_c/r^2 F_A = 9 times 10^9 Nm^2C^-2 times (2 times 10^-9 C)^2/(2 times 10^-2 m)^2 F_A = 9 times 10^-5 N since B and A are equal in magnitude therefore F_C = F_A = 9 times 10^-5 N since given triangle is an equilateral triangle therefore angle ACB = 60 degrees therefore angle ACF_H = angle F_H CB = 30 degrees \r\n F_H = F_V_A + F_V_B = 2F_V_A = 2F_A cos 30 degrees = 2 times 9 times 10^-5 N times cos 30 degrees (because F_V_A = F_V_B)