Question

Be sure to answer all parts. Draw a stepwise mechanism for the following reaction. OH OH H.C=0 HN N mida Draw the product of each step. :0 Il HN H2CO. draw structure ... proton transfer draw structure proton source

Answer 1

Answer :

The first step is the nucleophilic attack of the lone pair of N-atom to the carbonly carbon of CH₂=O ​​​​​​.

Then there is a proton transfer from (+)vely charged N-atom to negatively charged O-atom.

Then the lone pair of O-atom attacks the  H⁺ of the mild acid HA and generates A^-​​​​​​.

Then there is a lose of Water molecule (H₂O).

Then there is attack of the pi electron from the aromatic ring (Enhanced by the electron donating - OH group at ortho position) to the -CH₂ group with lose of aromaticity.

Then regain of aromaticity by lose of H⁺ by the A^- , generating the final product and HA ( acid).

The mechanism is given below -

u 7H02TH HO . (HH) aalmos nof ond | VHRt 에 I proton transfer anom 2u Stupthai of + . . . mild acid copaco HO .

CH. + H2O : I - comme VH + OH co +HA

(Answered)